This document is for a version of CakePHP that is no longer supported. Please upgrade to a newer release!
Virtual fields allow you to create arbitrary SQL expressions and assign them as fields in a Model. These fields cannot be saved, but will be treated like other model fields for read operations. They will be indexed under the model’s key alongside other model fields.
Creating virtual fields is easy. In each model you can define a
$virtualFields
property that contains an array of field =>
expressions. An example of a virtual field definition using MySQL
would be:
public $virtualFields = array(
'name' => 'CONCAT(User.first_name, " ", User.last_name)'
);
And with PostgreSQL:
public $virtualFields = array(
'name' => "User.first_name || \' \' || User.last_name"
);
In subsequent find operations, your User results would contain a
name
key with the result of the concatenation. It is not
advisable to create virtual fields with the same names as columns
on the database, this can cause SQL errors.
It is not always useful to have User.first_name fully
qualified. If you do not follow the convention (i.e. you have
multiple relations to other tables) this would result in an error.
In this case it may be better to just use
first_name || \' \' || last_name
without the Model
Name.
Creating virtual fields is straightforward and easy, interacting with virtual fields can be done through a few different methods.
Model::hasField() will return true if the model has a concrete field passed by the first parameter. By setting the second parameter of hasField() to true, virtualFields will also be checked when checking if a model has a field. Using the example field above:
// Will return false, as there is no concrete field called name
$this->User->hasField('name');
// Will return true as there is a virtual field called name
$this->User->hasField('name', true);
This method can be used to check if a field/column is a virtual field or a concrete field. Will return true if the column is virtual:
$this->User->isVirtualField('name'); //true
$this->User->isVirtualField('first_name'); //false
This method can be used to access the SQL expression that comprises a virtual field. If no argument is supplied it will return all virtual fields in a Model:
//returns 'CONCAT(User.first_name, ' ', User.last_name)'
$this->User->getVirtualField('name');
As stated earlier Model::find()
will treat virtual fields much
like any other field in a model. The value of a virtual field will
be placed under the model’s key in the resultset:
$results = $this->User->find('first');
// results contains the following
array(
'User' => array(
'first_name' => 'Mark',
'last_name' => 'Story',
'name' => 'Mark Story',
//more fields.
)
);
Since virtual fields behave much like regular fields when doing
finds, Controller::paginate()
will be able to sort by virtual fields too.
When you are using virtualFields and models with aliases that are not the same as their name, you can run into problems as virtualFields do not update to reflect the bound alias. If you are using virtualFields in models that have more than one alias it is best to define the virtualFields in your model’s constructor:
public function __construct($id = false, $table = null, $ds = null) {
parent::__construct($id, $table, $ds);
$this->virtualFields['name'] = sprintf(
'CONCAT(%s.first_name, " ", %s.last_name)', $this->alias, $this->alias
);
}
This will allow your virtualFields to work for any alias you give a model.
The following example allows you to have a counter of a hasMany association and enables you to use virtual fields. For example if you had the following sort link in your template:
// Create a sort link for a virtual field
$this->Paginator->sort('ProductsItems.Total','Items Total');
You could then use the following pagination setup in your controller:
$this->Products->recursive = -1;
// Products hasMany associations ProductsItems
$this->Products->ProductsItems->virtualFields['Total'] = 'count(ProductsItems.products_id)';
// Where ORM
$where = array(
'fields' => array(
'Products.*',
'count(ProductsItems.products_id) AS ProductsItems__Total',
),
'joins' => array(
array(
'table' => 'products_items',
'alias' => 'ProductsItems',
'type' => 'LEFT',
'conditions' => array(
'ProductsItems.products_id = Products.id',
)
)
),
'group' => 'ProductsItems.products_id'
);
// Set conditions Paginator
$this->paginate = $where;
// Get data
$data = $this->Paginator->paginate();
would return something like this:
Array
(
[0] => Array
(
[Products] => Array
(
[id] => 1234,
[description] => 'Text bla bla...',
)
[ProductsItems] => Array
(
[Total] => 25
)
)
[1] => Array
(
[Products] => Array
(
[id] => 4321,
[description] => 'Text 2 bla bla...',
)
[ProductsItems] => Array
(
[Total] => 50
)
)
)
Using functions in direct SQL queries will prevent data from being returned in the same array as your model’s data. For example this:
$this->Timelog->query(
"SELECT
project_id, SUM(id) as TotalHours
FROM
timelogs
AS
Timelog
GROUP BY
project_id;"
);
would return something like this:
Array
(
[0] => Array
(
[Timelog] => Array
(
[project_id] => 1234
)
[0] => Array
(
[TotalHours] => 25.5
)
)
)
If we want to group TotalHours into our Timelog array we should specify a
virtual field for our aggregate column. We can add this new virtual field on
the fly rather than permanently declaring it in the model. We will provide a
default value of 0
in case another query attempts to use this virtual field.
If that were to occur, 0
would be returned in the TotalHours column:
$this->Timelog->virtualFields['TotalHours'] = 0;
In addition to adding the virtual field we also need to alias our column using
the form of MyModel__MyField
like this:
$this->Timelog->query(
"SELECT
project_id, SUM(id) as Timelog__TotalHours
FROM
timelogs
AS
Timelog
GROUP BY
project_id;"
);
Running the query again after specifying the virtual field should result in a cleaner grouping of values:
Array
(
[0] => Array
(
[Timelog] => Array
(
[project_id] => 1234
[TotalHours] => 25.5
)
)
)
The implementation of virtualFields
has a few
limitations. First you cannot use virtualFields
on associated
models for conditions, order, or fields arrays. Doing so will
generally result in an SQL error as the fields are not replaced by
the ORM. This is because it difficult to estimate the depth at
which an associated model might be found.
A common workaround for this implementation issue is to copy
virtualFields
from one model to another at runtime when you
need to access them:
$this->virtualFields['name'] = $this->Author->virtualFields['name'];
or:
$this->virtualFields += $this->Author->virtualFields;